Soit la suite un=n3−4n+2u_n = n^3-4n +2un=n3−4n+2 pour n=0,1,2,3…n=0,1,2, 3\dotsn=0,1,2,3…
Calculer u0u_0u0, u1u_1u1 , u2u_2u2 et u3u_3u3
u0=2u_0 = 2u0=2, u1=−1u_1 = -1u1=−1, u2=2u_2 = 2u2=2 et u3=17u_3 = 17u3=17
u0=2u_0 = 2u0=2, u1=−1u_1 = -1u1=−1, u2=2u_2 = 2u2=2 et u3=−17u_3 = -17u3=−17
u0=−22u_0 = -22u0=−22 et u1=1u_1 = 1u1=1, u2=−1u_2 = -1u2=−1 et u3=−1u_3 = -1u3=−1